Wednesday, October 8, 2008
MALKIN
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Sunday, October 5, 2008
DATABASE2
SELECT companyname, MAX(price) AS presyo
FROM tblingredients AS i, tblvendors AS v, tblitems AS mi, tblmadewith AS mw
WHERE i.vendorid=v.vendorid AND i.ingredientid=mw.ingredientid AND mw.itemid=mi.itemid
GROUP BY v.vendorid, companyname;
SELECT DISTINCT (companyname)
FROM tblingredients AS i, tblvendors AS v, tblitems AS mi, tblmadewith AS mw
WHERE i.vendorid=v.vendorid AND i.ingredientid=mw.ingredientid AND mw.itemid=mi.itemid AND mi.name='Fruit Plate';
SELECT v2.companyname
FROM tblvendors AS v1, tblvendors AS v2
WHERE v1.vendorid=v2.referredby AND v1.companyname= 'Veggies_R_Us';
SELECT i.name,
m.name
FROM tblitems AS i, tblmeals AS m, tblpartof AS p
WHERE i.itemid=p.itemid AND p.mealid=m.mealid;
SELECT i.name
FROM tblingredients AS i, tblmadewith AS mw
WHERE i.ingredientid=mw.ingredientid AND inventory=quantity;
SELECT ingredientid
FROM tblingredients, tblvendors
WHERE name=companyname;
SELECT *
FROM tblmeals, tblpartof;
SELECT m.name AS meal, i.name AS item
FROM tblmeals AS m, tblpartof AS p, tblitems AS i
WHERE m.mealid=p.mealid AND
i.itemid=p.itemid;
SELECT *
FROM tblmeals AS m1, tblmeals AS m2;
SELECT m.name AS meal, i.name AS item
FROMtblmeals AS m, tblpartof AS p, tblitems AS i
WHERE i.itemid=p.itemid;
SELECT tblitems.name, ing.name
FROM tblitems,tblmadewith AS mw, tblingredients AS ing
WHERE tblitems.itemid=mw.itemid AND mw.ingredienti
d=ing.ingredientid AND 3*mw.quantity>ing.inventory;
SELECT a.name
FROM tblitems AS a, tblitems AS q
WHERE a.price>q.price AND q.name='Garden Salad';
SELECT DISTINCT (i.name)
FROM tblitems AS
a, tblitems AS q, tblmadewith AS m, tblingredients AS i
WHERE a.price>q.price AND q.name='Garden Salad' AND i.ingredientid=m.ingredientid AND m.itemid=a.itemid;
SELECT i1.name, COUNT(*) AS rank
FROM tblingredients AS i1, tblingredients AS i2
WHERE i1.name>=i2.name
GROUP BY i1.ingredientid, i1.name;
SELECT name
FROM tblingredients AS i INNER JOIN tblvendors AS v ON i.vendorid=v.vendorid
WHERE v.companyname='Veggies_R_Us';
SELECT i1.name
FROM tblitems AS i1 INNER JOIN tblitems AS i2 ON i1.price>i2.price
WHERE i2.name='Garden Salad';
SELECT companyname, i.vendorid, i.name
FROM tblvendors AS v INNER JOIN tblingredients AS i ON v.vendorid=i.vendorid;
Saturday, October 4, 2008
DATABASE
SQL STATEMENTS AND OUTPUTS:
SELECT i.name, m.quantity, d.name, d.unitprice, (d.unitprice*m.quantity) AS subtotal
FROM tblitems AS i, tblmadewith AS m, tblingredients AS d
WHERE i.itemid=m.itemid And i.name Like "fruit plate" And d.ingredientid=m.ingredientid;
SELECT tblvendors.vendorid, tblingredients.name, tblvendors.companyname
FROM tblingredients, tblvendors
WHERE tblingredients.vendorid=tblvendors.vendorid;
SELECT name
FROM tblingredients, tblvendors
WHERE tblingredients.vendorid=tblvendors.vendorid AND companyname='Veggies_R_Us';
SELECT tblstores.storeid, tblorders.price
FROM tblorders, tblstores
WHERE tblorders.storeid=tblstores.storeid AND state='CA';
SELECT state, SUM(price)
FROM tblstores, tblorders
WHERE tblstores.storeid=tblorders.storeid
GROUP BY state;
SELECT v.vendorid AS ["VENDOR ID"], name
FROM tblingredients AS i, tblvendorsAS v
WHERE i.vendorid=v.
vendorid And v.companynameIn ('Veggies_R_Us','SpringWater Supply')
ORDER BYv.vendorid;
SELECT DISTINCT mi.name, price
FROM tblingredients AS i, tblvendors AS v, tblitems AS mi, tblmadewith AS mw
WHERE i.vendori
d=v.vendorid AND i.ingredientid=mw.ingredientid AND mw.itemid=mi.itemid AND
companyname='Veggies_R_Us';